Ionic Array
radii of a cation and anion???!!!! HELP PLEASE!!!?
The crystal structure of an ionic compound consists of alternating cations and anions lying next to each other in three dimensions. If the cation radius is 57.6% of the anion radius and the distance between the cation nuclei is 546 pm, what are the radii of the two ions? (Note: This ionic compound is a three dimensional array. The cation to cation, center-to-center distance specified is through the center of the anion.)
anion
From your information, the combined diameters of the cation and the anion is 546 pm. This means that the sum of the radii is
546 pm / 2 = 273 pm = cation radius + anion radius.
You know that 57.6 % of the anion radius is the cation radius.
273 pm = 0.576 * anion radius + anion radius = 1.576 * anion radius
The Anion radius is (273 / 1.576) pm
The Cation radius is the Anion radius * 0.576
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